题目:
Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -.
Example:
Given a = 1 and b = 2, return 3.
解题思路:用异或算不带进位的和,用与并左移一位来算进位,再把两者相加即可,直到进位为全0。递归的解法如下:
public class Solution {
public int getSum(int a, int b) {
if(b==0) return a;
int sum = a ^ b;
int carry = (a & b) << 1;
return getSum(sum, carry);
}
}