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最新推荐文章于 2025-09-05 14:01:23 发布

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本文介绍了解决Python Challenge网站上一个谜题的方法，该谜题要求将字符串中的每个字母向后移动两个位置来解密隐藏信息，并提供了三种实现方式：逐字符处理、使用string.maketrans()函数及string.join()函数。

链接：http://www.pythonchallenge.com/pc/def/map.html

解题思路：

1，首先根据字符位移处理注释字符串

#Get ASC2 number of a character

number = ord(char)

#Get the character given by a ASC2 number

char = chr(number)

import string

a = """ g fmnc wms bgblr rpylqjyrc gr zw fylb. rfyrq ufyr amknsrcpq ypc dmp. bmgle gr gl zw fylb gq glcddgagclr ylb rfyr'q ufw rfgq rcvr gq qm jmle. sqgle qrpgle.kyicrpylq() gq pcamkkclbcb. lmu ynnjw ml rfc spj."""
if __name__ == "__main__":
r = ""
for i in a:
    if i in string.letters:
        i = chr(ord(i) + 2)
        if i > 'z':
            i = chr(ord(i) - 26)
    r += i
print r

翻译出：i hope you didnt translate it by hand. thats what computers are for. doing it in by hand is inefficient and that's why this text is so long. using string.maketrans() is recommended. now apply on the url.

#用提示的string.maketrans()方法：
port string

url = "map"
hint = """ g fmnc wms bgblr rpylqjyrc gr zw fylb. rfyrq ufyr amknsrcpq ypc dmp. bmgle gr gl zw fylb gq glcddgagclr ylb rfyr'q ufw rfgq rcvr gq qm jmle.
sqgle qrpgle.kyicrpylq() gq pcamkkclbcb. lmu ynnjw ml rfc spj. """

trans = string.maketrans("abcdefghijklmnopqrstuvwxyz","cdefghijklmnopqrstuvwxyzab")
print(hint.translate(trans))
print(url.translate(trans))

#用string.join()方法简洁的两行代码
import string
print(''.join(chr(ord(i) + 2) for i in 'map'))