<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title><![CDATA[ch12370的博客]]></title><description><![CDATA[]]></description><link>https://blog.youkuaiyun.com/ch12370</link><language>zh-cn</language><generator>https://blog.youkuaiyun.com/</generator><copyright><![CDATA[Copyright &copy; ch12370]]></copyright><item><title><![CDATA[多线程之龟兔赛跑]]></title><link>https://blog.youkuaiyun.com/ch12370/article/details/129954480</link><guid>https://blog.youkuaiyun.com/ch12370/article/details/129954480</guid><author>ch12370</author><pubDate>Tue, 04 Apr 2023 15:43:53 +0800</pubDate><description><![CDATA[用 Thread.currentThread().getName().equals("兔子") 选中线程,让兔子十步一睡。每跑一步进来看一下,有没有产生胜利者,有的话就把他的名字装入winner里面去,并打印胜利者。Thread.currentThread().getName() 默认选择当前使用的线程。实现的runnable方法 重写run方法。比赛会有一个胜利者,所以先定义胜利者。]]></description><category></category></item><item><title><![CDATA[一个简易的生产消费队列思路]]></title><link>https://blog.youkuaiyun.com/ch12370/article/details/129953657</link><guid>https://blog.youkuaiyun.com/ch12370/article/details/129953657</guid><author>ch12370</author><pubDate>Tue, 04 Apr 2023 15:25:50 +0800</pubDate><description><![CDATA[Exception in thread "生产者线程" Exception in thread "消费者线程" java.lang.IllegalMonitorStateException。3:if判断,生产/消费是否超值,超出就要做相应的对策,如wait线程等待并释放锁。2:多线程一定要加synchronize锁,不加会报错。4:最后一定要notifyAll,唤醒所有线程。1:while里面20是打算生产/消费多少总数。定义好了就开始写具体的生产者和消费者。学习途中随手记录(轻喷)]]></description><category></category></item><item><title><![CDATA[Gitee 上传与下载]]></title><link>https://blog.youkuaiyun.com/ch12370/article/details/128131315</link><guid>https://blog.youkuaiyun.com/ch12370/article/details/128131315</guid><author>ch12370</author><pubDate>Thu, 01 Dec 2022 14:28:38 +0800</pubDate><description><![CDATA[Gitee的上传与下载]]></description><category></category></item></channel></rss>