Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
法1: Using a HashSet to detect whether the link list has a circle
法2: Using slow and fast pointer to detect.
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
if(head == null)
return false;
HashSet<ListNode> set = new HashSet<ListNode>();
while(head != null){
if(set.contains(head))
return true;
else
set.add(head);
head = head.next;
}
return false;
}
}
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
if(head == null)
return false;
ListNode slow = head;
ListNode fast = head;
while(fast != null && fast.next != null){
slow = slow.next;
fast = fast.next.next;
if(slow == fast)
return true;
}
return false;
}
}