/*
SQL> 查询10和20号部门的员工
SQL> 1. select * from emp where deptno=10 or deptno=20;
SQL> 2. select * from emp where deptno in (10,20);
SQL> 3. 集合运算
SQL> select * from emp where deptno=10
SQL> 加上
SQL> select * from emp where deptno=20
*/
--select语句相加减,通过集合运算的方式
SQL> select * from emp where deptno=10
2 union
3 select * from emp where deptno=20;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- -------------- ---------- ---------- ----------
7369 SMITH CLERK 7902 17-12月-80 800 20
7566 JONES MANAGER 7839 02-4月 -81 2975 20
7782 CLARK MANAGER 7839 09-6月 -81 2450 10
7788 SCOTT ANALYST 7566 19-4月 -87 3000 20
7839 KING PRESIDENT 17-11月-81 5000 10
7876 ADAMS CLERK 7788 23-5月 -87 1100 20
7902 FORD ANALYST 7566 03-12月-81 3000 20
7934 MILLER CLERK 7782 23-1月 -82 1300 10
已选择 8 行。
SQL> select deptno,job,sum(sal) from emp group by rollup(deptno,job);
DEPTNO JOB SUM(SAL)
---------- --------- ----------
10 CLERK 1300
10 MANAGER 2450
10 PRESIDENT 5000
10 8750
20 CLERK 1900
20 ANALYST 6000
20 MANAGER 2975
20 10875
30 CLERK 950
30 MANAGER 2850
30 SALESMAN 5600
DEPTNO JOB SUM(SAL)
---------- --------- ----------
30 9400
29025
已选择 13 行。
SQL> select deptno,job,sum(sal) from emp group by deptno,job
2 union
3 select deptno,sum(sal) from emp group by deptno
4 union
5 select sum(sal) from emp;
select deptno,sum(sal) from emp group by deptno
*
第 3 行出现错误:
ORA-01789: 查询块具有不正确的结果列数
SQL> /*
SQL> 注意的问题:
SQL> 1、参与运算的各个集合必须列数相同且类型一致 ,如果列不一样可以使用加列的方式to_char(null)
SQL> 2、采用第一个集合作为最后生成的表头
SQL> 3、order by永远在最后
SQL> 4、括号改变执行的顺序
SQL> */
SQL> select deptno,job,sum(sal) from emp group by deptno,job
2 union
3 select deptno,to_char(null),sum(sal) from emp group by deptno
4 union
5 select to_number(null),to_char(null),sum(sal) from emp;
DEPTNO JOB SUM(SAL)
---------- --------- ----------
10 CLERK 1300
10 MANAGER 2450
10 PRESIDENT 5000
10 8750
20 ANALYST 6000
20 CLERK 1900
20 MANAGER 2975
20 10875
30 CLERK 950
30 MANAGER 2850
30 SALESMAN 5600
DEPTNO JOB SUM(SAL)
---------- --------- ----------
30 9400
29025
已选择 13 行。
SQL> --break on deptno skip 2
SQL> host cls
SQL> --SQL 执行的时间
SQL>
SQL> set timing on
SQL> select deptno,job,sum(sal) from emp group by rollup(deptno,job);
DEPTNO JOB SUM(SAL)
---------- --------- ----------
10 CLERK 1300
10 MANAGER 2450
10 PRESIDENT 5000
10 8750
20 CLERK 1900
20 ANALYST 6000
20 MANAGER 2975
20 10875
30 CLERK 950
30 MANAGER 2850
30 SALESMAN 5600
DEPTNO JOB SUM(SAL)
---------- --------- ----------
30 9400
29025
已选择 13 行。
已用时间: 00: 00: 00.01
SQL> select deptno,job,sum(sal) from emp group by deptno,job
2 union
3 select deptno,to_char(null),sum(sal) from emp group by deptno
4 union
5 select to_number(null),to_char(null),sum(sal) from emp;
DEPTNO JOB SUM(SAL)
---------- --------- ----------
10 CLERK 1300
10 MANAGER 2450
10 PRESIDENT 5000
10 8750
20 ANALYST 6000
20 CLERK 1900
20 MANAGER 2975
20 10875
30 CLERK 950
30 MANAGER 2850
30 SALESMAN 5600
DEPTNO JOB SUM(SAL)
---------- --------- ----------
30 9400
29025
已选择 13 行。
已用时间: 00: 00: 00.01
SQL> select deptno,job,sum(sal) from emp group by deptno,job
2 union
3 select deptno,to_char(null),sum(sal) from emp group by deptno
4 union
5 select to_number(null),to_char(null),sum(sal) from emp;
DEPTNO JOB SUM(SAL)
---------- --------- ----------
10 CLERK 1300
10 MANAGER 2450
10 PRESIDENT 5000
10 8750
20 ANALYST 6000
20 CLERK 1900
20 MANAGER 2975
20 10875
30 CLERK 950
30 MANAGER 2850
30 SALESMAN 5600
DEPTNO JOB SUM(SAL)
---------- --------- ----------
30 9400
29025
已选择 13 行。
已用时间: 00: 00: 00.03
SQL> --SQL优化 4、 尽量不要使用集合运算
SQL> set timing off
SQL> spool off
--交集的关键字INTERSECT
--差集的关键字minus
oracle中的集合运算
最新推荐文章于 2023-09-26 14:09:41 发布