Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given input array nums = [3,2,2,3], val = 3
Your function should return length = 2, with the first two elements of nums being 2.
Code:
class Solution
{
public:
int removeElement(vector<int>& nums, int val)
{
nums.erase(remove(nums.begin(),nums.end(),val),nums.end());
return nums.size();
}
};
本文介绍了一种在C++中高效移除数组内特定值的方法,并返回新的有效长度。利用标准库函数`std::remove`配合`vector`的`erase`方法实现原地删除,不使用额外空间且符合常数内存限制。
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