Write an efficient algorithm that searches for a value in an m x n matrix. This matrix
has the following properties:
Integers in each row are sorted in ascending from left to right.
Integers in each column are sorted in ascending from top to bottom.
For example,
Consider the following matrix:
[ [1, 4, 7, 11, 15], [2, 5, 8, 12, 19], [3, 6, 9, 16, 22], [10, 13, 14, 17, 24], [18, 21, 23, 26, 30] ]Given target = 5, return true.
Given target = 20, return false.
从左上角开始,大于target向前,小于向下。
public class Solution {
public boolean searchMatrix(int[][] matrix, int target) {
if(matrix==null||matrix.length<=0)
return false;
int m=matrix.length;
int n=matrix[0].length;
int i=0,j=n-1;
while(i<m&&j>=0){
int tmp=matrix[i][j];
if(tmp>target)
j--;
else if(tmp<target)
i++;
else
return true;
}
return false;
}
}