C++ 判断是否存在Emjoi表情

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于 2018-10-06 16:43:15 发布 · 1.5k 阅读

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#cocos2dx c++

C++ 判断是否存在Emjoi表情

弄了很久才弄出来，做个记录

bool isContainEmoji(const std::string str)
	{
		bool bContain = false;
		std::u16string ut16 = {};
		if (StringUtils::UTF8ToUTF16(str, ut16))
		{
			if (false == ut16.empty())
			{
				size_t len = ut16.length();
				for (size_t i = 0; i < len; ++i)
				{
					char16_t hs = ut16[i];
					if (0xd800 <= hs && hs <= 0xdbff)
					{
						if (ut16.length() > (i + 1))
						{
							char16_t ls = ut16[i + 1];
							int uc = ((hs - 0xd800) * 0x400) + (ls - 0xdc00) + 0x10000;
							if (0x1d000 <= uc && uc <= 0x1f77f)
							{
								bContain = true;
								break;
							}
						}
					}
					else
					{
						if (0x2100 <= hs && hs <= 0x27ff)
						{
							bContain = true;
						}
						else if (0x2B05 <= hs && hs <= 0x2b07)
						{
							bContain = true;
						}
						else if (0x2934 <= hs && hs <= 0x2935)
						{
							bContain = true;
						}
						else if (0x3297 <= hs &&a