一个数组中只有两个数字是出现一次,其他所有数字都出现了两次。编写一个函数找出这两个只出现一次的数字。

找单身狗 :一个数组中只有两个数字是出现一次,其他所有数字都出现了两次。编写一个函数找出这两个只出现一次的数字。 找单身狗 :一个数组中只有两个数字是出现一次,其他所有数字都出现了两次。编写一个函数找出这两个只出现一次的数字。 一、题目解析 数组{1,2,3,4,1,2,3,4,7,8},即编写函数找到7,8 二,异或性质 (1)a^a=0; (2)a^0=a; (3)a^(b^c)=b^(a^c)=c^(a^b); 三、思路 (1)对于出现两次的元素,使用“异或”操作后结果肯定为0,那么我们就可以遍历一遍数... 阅读详情

一个数组中只有两个数字是出现一次,其他所有数字都出现了两次。编写一个函数找出这两个只出现一次的数字。

#include<stdio.h>
#include<string.h>
#include<Windows.h>
#include <assert.h>
void search(int a[], int num)
{
   
   
	assert(a);
	assert(num > 0);
	int *x = (int *)malloc(
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