SELECT
s1.employee_id,
s1.score,
s1.date
FROM
score s1
JOIN ( SELECT employee_id, MAX( date ) date FROM score GROUP BY employee_id ) s2
ON s1.employee_id = s2.employee_id AND s2.date = s1.date
获取每个员工的最新记录
于 2022-03-01 16:51:11 首次发布