题目链接:点击打开链接
思路:建树,存储相关信息(数值,左儿子,右儿子,父节点,深度)。对于每类询问,做相应判断即可。
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <map>
using namespace std;
int data[105],le[105],rig[105];
int fa[105],level[105];
int root;
map<int,int> m;
void add(int &r,int father,int depth,int loc){
if(r == -1){
r = loc;
fa[loc] = father;
level[loc] = depth;
return;
}
if(data[loc] < data[r]){
add(le[r],r,depth + 1,loc);
}
else{
add(rig[r],r,depth + 1,loc);
}
}
int main(){
int n;
scanf("%d",&n);
root = -1;
memset(le,-1,sizeof(le));
memset(rig,-1,sizeof(rig));
for(int i = 1;i <= n;i++){
scanf("%d",&data[i]);
add(root,-1,1,i);
m[data[i]] = i;
}
int q,a,b;
string aa;
bool flag;
scanf("%d",&q);
while(q--){
flag = false;
scanf("%d",&a);
cin>>aa;
if(aa == "is"){
cin>>aa>>aa;
if(aa == "root"){
if(m.find(a) != m.end() && data[root] == a) flag = true;
}
else if(aa == "parent"){
cin >> aa;
cin >> b;
if(m.find(a) != m.end() && m.find(b) != m.end() && fa[m[b]] == m[a]) flag = true;
}
else if(aa == "left"){
cin >> aa >> aa;
cin >> b;
if(m.find(a) != m.end() && m.find(b) != m.end() && fa[m[a]] == m[b] && a < b) flag = true;
}
else{
cin >> aa >> aa;
cin >> b;
if(m.find(a) != m.end() && m.find(b) != m.end() && fa[m[a]] == m[b] && a > b) flag = true;
}
}
else{
cin >> b;
cin >> aa >> aa;
if(aa == "siblings"){
if(m.find(a) != m.end() && m.find(b) != m.end() && fa[m[a]] == fa[m[b]]) flag = true;
}
else{
cin >> aa >> aa >> aa;
if(m.find(a) != m.end() && m.find(b) != m.end() && level[m[a]] == level[m[b]]) flag = true;
}
}
puts(flag?"Yes":"No");
}
return 0;
}