浙大ZOJ PAT practice – 1005

最新推荐文章于 2020-01-17 16:33:59 发布

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最新推荐文章于 2020-01-17 16:33:59 发布

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文章标签： output each integer string input file

本文链接：https://blog.youkuaiyun.com/caoxulei/article/details/6035626

本文提供了一道PATpractice题目的详细解答，题目要求输入一个非负整数N，计算N所有位上的数字之和，并用英文单词形式输出每位数字。示例输入为12345，输出为“one five”。文章给出了完整的C++代码实现，包括字符串转换及英文单词映射。

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PAT practice - 1005
Spell It Right (20)
Time Limit: 1 Second Memory Limit: 32768 KB
Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.

Input Specification:

Each input file contains one test case. Each case occupies one line which contains an N (<= 10100).

Output Specification:

For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.

Sample Input:
12345
Sample Output:
one five

#include 
#include 
#include 
using namespace std;
int main(){
    string str;
    cin>> str;
    int sum=0;
    int i=0;
    for(;str[i]!='/0';i++)
    sum+=str[i]-'0';   //计算每个数的和
    stringstream ssum; //将int转换为string
    ssum<>str;
   i=0;
   int num=0;
   for(;str[i]!='/0';i++){
	   cout<<((i==0)?"":" ");//除第一个数除外 输出空格
    num=str[i]-'0';
   switch(num){
   case 1 : cout<<"one" ; break;
   case 2 : cout<<"two" ; break;
   case 3 : cout<<"three";break;
   case 4 : cout<<"four"; break;
   case 5 : cout<<"five" ;break;
   case 6 : cout<<"six";  break;
   case 7 : cout<<"seven";break; 
   case 8 : cout<<"eight";break;
   case 9 : cout<<"nine" ;break; 
   case 0 : cout<<"zero"; break;
   }
 }
  return 0;   
}