Given an array of integers, find two numbers such that they add up to a specific target number. The function twoSum should return indices of the two numbers such that they add up to the target, where index1 must be less than index2. Please note that your returned answers (both index1 and index2) are not zero-based. You may assume that each input would have exactly one solution.
Input: numbers={2, 7, 11, 15}, target=9
Output: index1=1, index2=2
public class Solution {
public int[] twoSum(int[] numbers, int target) {
// IMPORTANT: Please reset any member data you declared, as
// the same Solution instance will be reused for each test case.
int len = numbers.length;
int[] index = new int[2];
HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
for (int i = 0; i < len; i++) {
if (!map.containsKey(numbers[i])) {
map.put(target - numbers[i], i);
} else {
index[0] = map.get(numbers[i]) + 1;
index[1] = i + 1;
}
}
return index;
}
}
本文介绍了一种解决两数之和问题的有效算法。给定一个整数数组及目标值,通过使用哈希表,快速找到两个数的下标,使它们相加等于目标值。该算法将复杂度降低到O(n),适用于多种编程场景。
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