splice(start,deleteCount,val1,val2,...):从start位置开始删除deleteCount项,并从该位置起插入val1,val2,...
var a = [1,2,3,4,5];
var b = a.splice(2,2,7,8,9); //a:[1,2,7,8,9,5] b:[3,4]
var b = a.splice(0,1); //同shift
a.splice(0,0,-2,-1); var b = a.length; //同unshift
var b = a.splice(a.length-1,1); //同pop
a.splice(a.length,0,6,7); var b = a.length; //同push
splice(start,deleteCount,val1,val2,...):从start位置开始删除deleteCount项
最新推荐文章于 2023-06-16 06:59:52 发布