You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.
Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.
Credits:
Special thanks to @ifanchu for adding this problem and creating all test cases. Also thanks to @ts for adding additional test cases.
我想到了动态规划的问题。这题可以看做是简单的DP问题,用A[0]表示没有rob当前house的最大money,A[1]表示rob了当前house的最大money,那么A[0] 等于rob或者没有rob上一次house的最大值

这篇博客探讨了LeetCode中的198题——House Robber,这是一个关于动态规划的算法问题。博主介绍了如何通过动态规划策略,计算在不触发警报的情况下能偷窃到的最多金额。博客提到了两种动态规划解决方案,并提到还存在一种状态压缩的方法,但博主表示尚未研究。
订阅专栏 解锁全文

413

被折叠的 条评论
为什么被折叠?



