题目描述:
有n个正整数,请将它们拼接成一排,组成一个最大的多位整数。例如:n=3时,3个整数13,312,343拼接成的最大整数为:34331213。
输入
第一行为正整数个数n(n<=10000),第二行n个以空格相隔的正整数(integer类型)
输出
输出一行表示答案
样例输入
3
13 312 343
样例输出
34331213
代码:
import java.util.Arrays;
import java.util.Comparator;
import java.util.Scanner;
public class Test {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
if(n==0) return;
String[] res = new String[n];
for (int i = 0; i < n; i++)
res[i] = sc.nextInt()+"";
if(n==1) {System.out.println(res[0]);return;}
Comparator cmp = new MyComparator();
Arrays.sort(res,cmp);
/*for(String str : res) {
System.out.println(str);
}*/
StringBuilder buf=new StringBuilder();
for (int i = n-1; i >=0; i--)
buf.append(res[i]);
System.out.println(buf.toString());
}
static class MyComparator implements Comparator<String>{
@Override
public int compare(String o1, String o2) {
int len1 = o1.length();
int len2 = o2.length();
int lim = Math.min(len1, len2);
char v1[] = o1.toCharArray();
char v2[] = o2.toCharArray();
int k = 0;
while (k < lim) {
char c1 = v1[k];
char c2 = v2[k];
if (c1 != c2) {
return c1 - c2;
}
k++;
}
return len2 - len1;
}
}
}