题目描述
给定一个数组和滑动窗口的大小,找出所有滑动窗口里数值的最大值。例如,如果输入数组{2,3,4,2,6,2,5,1}及滑动窗口的大小3,那么一共存在6个滑动窗口,他们的最大值分别为{4,4,6,6,6,5}; 针对数组{2,3,4,2,6,2,5,1}的滑动窗口有以下6个: {[2,3,4],2,6,2,5,1}, {2,[3,4,2],6,2,5,1}, {2,3,[4,2,6],2,5,1}, {2,3,4,[2,6,2],5,1}, {2,3,4,2,[6,2,5],1}, {2,3,4,2,6,[2,5,1]}。
题解
#include <iostream>
#include <vector>
#include <deque>
using namespace std;
vector<int> maxInWindows(const vector<int> &num, unsigned int size) {
vector<int> v;
deque<int> d;
for (unsigned int i = 0; i < num.size(); ++i) {
while (d.size() && num[d.back()] <= num[i])
d.pop_back();
if (d.size() && i - d.front() + 1 > size)
d.pop_front();
d.push_back(i);
if (size && i + 1 >= size)
v.push_back(num[d.front()]);
}
return v;
}
int main() {
ios::sync_with_stdio(false);
vector<int> v, res;
int n, k, tmp;
cin >> n >> k;
for (int i = 0; i < n; i++) {
cin >> tmp;
v.push_back(tmp);
}
res = maxInWindows(v, k);
for (auto it = res.begin(); it != res.end(); ++it)
cout << *it << " ";
return 0;
}