POJ 2080 Calendar

 

Calendar

Time Limit: 1000MS		Memory Limit: 30000K
Total Submissions: 6463		Accepted: 2430

Description

A calendar is a system for measuring time, from hours and minutes, to months and days, and finally to years and centuries. The terms of hour, day, month, year and century are all units of time measurements of a calender system. 
According to the Gregorian calendar, which is the civil calendar in use today, years evenly divisible by 4 are leap years, with the exception of centurial years that are not evenly divisible by 400. Therefore, the years 1700, 1800, 1900 and 2100 are not leap years, but 1600, 2000, and 2400 are leap years. 
Given the number of days that have elapsed since January 1, 2000 A.D, your mission is to find the date and the day of the week.

Input

The input consists of lines each containing a positive integer, which is the number of days that have elapsed since January 1, 2000 A.D. The last line contains an integer −1, which should not be processed. 
You may assume that the resulting date won’t be after the year 9999.

Output

For each test case, output one line containing the date and the day of the week in the format of "YYYY-MM-DD DayOfWeek", where "DayOfWeek" must be one of "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday" and "Saturday".

Sample Input

1730
1740
1750
1751
-1

Sample Output

2004-09-26 Sunday
2004-10-06 Wednesday
2004-10-16 Saturday
2004-10-17 Sunday

Source

Shanghai 2004 Preliminary

 

 

/*
一个日历程序，输入一个自然数n，然后给出距离2000.01.01 n天的日期以及星期
*/

#include <iostream> using namespace std; int days, year, day; int mondDays[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; //判断是不是闰年 inline bool isLeap(int year) { return (year % 100 == 0 && year % 400 == 0) || (year % 100 != 0 && year % 4 == 0); } int main() { int i; while(scanf("%d", &days) && days != - 1) { days += 1; year = 2000; day = 0; //找到可以覆盖的年份 while(true) { bool leapyear = isLeap(year); int tempday = day; if(leapyear) tempday += 366; else tempday += 365; if(tempday < days) { year++; day = tempday; } else break; } int restDay = days - day, countD = 0; //找到可以覆盖的月份 for(i = 1; i <= 12; i++) { int curdays = mondDays[i]; if(i == 2 && isLeap(year)) curdays += 1; if(countD + curdays < restDay) countD += curdays; else break; } //打印年月日 printf("%d-", year); if(i < 10) printf("0%d-", i); else printf("%d-", i); restDay = restDay - countD; if(restDay < 10) printf("0%d ", restDay); else printf("%d ", restDay); //计算星期，2000.01.01是星期六 days--; int type = (6 + days % 7) % 7; if(type == 0) printf("Sunday"); else if(type == 1) printf("Monday"); else if(type == 2) printf("Tuesday"); else if(type == 3) printf("Wednesday"); else if(type == 4) printf("Thursday"); else if(type == 5) printf("Friday"); else printf("Saturday"); printf("/n"); } return 0; }