1001. A+B Format (20)

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本文介绍了一个简单的编程问题：计算两个整数a和b的和，并将结果以标准格式输出，即使用逗号作为千位分隔符。文章提供了一段C语言代码实现，通过输入两个整数，程序会正确地显示带有千位分隔符的结果。

1001. A+B Format (20)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input

-1000000 9

Sample Output

-999,991#include<stdio.h>
int main()
{
    int i=0,flag=0,a,b,sum;
    char str[9];
    while(scanf("%d%d",&a,&b)!=EOF)
    {
        flag=0;
         sum = a+b;
        if(sum<0)
        {
            sum = -sum;
            printf("-");
        }
        if(sum==0){printf("0");}
        for(i=0;sum>0;i++)
        {
            str[i] = sum%10+'0';//数字转换为字符
            sum = sum/10;
            if(flag == 2 && sum!=0)
            {
                i++;
                str[i]=',';
                flag=0;
            }
            else
                flag++;
        }
        i--;
        for(;i>=0;i--)
        {
            printf("%c",str[i]);

        }
        printf("\n");

    }
    return 0;
}