Prime Ring Problem
Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 25319 Accepted Submission(s): 11301
Note: the number of first circle should always be 1.

You are to write a program that completes above process.
Print a blank line after each case.
6 8
Case 1: 1 4 3 2 5 6 1 6 5 2 3 4 Case 2: 1 2 3 8 5 6 7 4 1 2 5 8 3 4 7 6 1 4 7 6 5 8 3 2 1 6 7 4 3 8 5 2
此题要用到递归
代码:
#include<stdio.h>
//此函数为判断素数
int prime(int m)
{
int n = 0 ;
for(int i = 2 ; i < m ; i++)
{
if(m % i == 0 )
n++;
}
if( n==0 )
return 1;
else
return 0;
}
//递归
int a[100];
int flag[100] = {0};
void DFS(int x,int n)
{
int i = 0 , j = 0 , m = 0 ;
for(i = 2 ; i <= n ; i++)
{
int m = 0 ;
m = prime(a[x-1]+i);
if(m == 0 || flag[i])//判断当两个数相加不是素数并且这个数被标记
continue;
a[x] = i ;
flag[i] = 1;
DFS(x+1,n);
flag[i] = 0 ;
}
if(prime(a[x - 1]+1) == 1 && x == n)
{
for( i = 0 ; i < n-1 ; i++)
printf("%d ", a[i]);
printf("%d\n",a[n-1]);
return ;
}
}
int main()
{
int n = 0 , b = 1 ;
while(~scanf("%d",&n))
{
a[0] = 1 ;
int x = 1 ;
printf("Case %d:\n",b);
DFS(x,n);
printf("\n");
b++;
}
return 0;
}