for循环实现求最小值，最大值和平均值C++实现

#include <bits/stdc++.h>
using namespace std;


int main() {
	
	int n, tem, max, min;
	float sum1 = 0;
	cin >> n;
	cin >> tem;
	max = tem;
	min = max;
	sum1 = sum1 + tem;
	//注意i的输入次数和n的次数，少等于号 
	for(int i=1; i<n; i++) {
		cin >> tem;
		if (tem > max) {
			max = tem;
		}
		if (tem < min) {
			min = tem;
		}
		sum1 = sum1 + tem;
	}
	
	cout << min << " " << max <<  " " << (sum1 / (n * 1.0)); 
	
	return 0;
}