select * from student where name like '%a%';='%[ao]%' []匹配其中任一字符select * from student where name like '%[a][o]%';
select * from student where name not like '%a%';select * from student where name like 'ja%';='%[jn,]%'select * from student where name not like '%[j,n]%';='%[jna,]%'select * from student where name like '%[j,n,a]%';
='%[^jason,]%' 不包含jason,任一字符的字符串,匹配','的情况下前一种写法易读select * from student where name like '%[^ja,as,on]%';='%[jaon_]%'select * from student where name like '%[ja_on]%';
like 模糊查询
最新推荐文章于 2024-10-17 10:15:00 发布