#转转盘10000次,求一二三等奖的次数
mport random
if __name__ == "__main__":
a, b, c = 0, 0, 0
for i in range(10000):
r = int(random.random() * 360)
if 0 <= r < 10:
a += 1
elif 10 <= r < 120:
b += 1
elif 120 <= r < 360:
c += 1
print("一等奖{}个,二等奖{}个,三等奖{}个。".format(a, b, c))
转10000次转盘,求次数
最新推荐文章于 2025-05-28 01:15:00 发布