above average

最新推荐文章于 2018-11-25 17:36:23 发布

原创最新推荐文章于 2018-11-25 17:36:23 发布 · 750 阅读

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本文介绍了一个简单的程序，该程序能够处理多个班级的成绩数据，并计算出每个班级中成绩高于平均分的学生所占的百分比。输入包括班级数量及各班学生的成绩，输出则是每个班级高于平均分的学生比例。

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Description

It is said that 90% of frosh expect to be above average in their class. You are to provide a reality check.

Input

The first line of standard input contains an integer C, the number of test cases. C data sets follow. Each data set begins with an integer, N, the number of people in the class (1 <= N <= 1000). N integers follow, separated by spaces or newlines, each giving the final grade (an integer 0 <= final grade <= 100) of a student.

Output

For each case you are to output a line giving the percentage of students whose grade is above average, rounded to 3 decimal places.

Sample Input

5
5 50 50 70 80 100
7 100 95 90 80 70 60 50
3 70 90 80
3 70 90 81
9 100 99 98 97 96 95 94 93 91

Sample Output

40.000%
57.143%
33.333%
66.667%
55.556%

#include<iostream>
using namespace std;
int main()
{
   int n,m,s[1001],i;
   cin>>n;
   while(n--)
   {
       int sum=0;
       int avr=0;
       int num=0;
      cin>>m;
      for(i=0;i<m;i++)
      {
        cin>>s[i];
        sum+=s[i];
      }
      avr=sum/m;
       for(i=0;i<m;i++)
       {
         if(s[i]>avr)
             num++;

       }
      cout.setf(ios::fixed);
      cout.precision(3);
      cout<<(num*1.0/m*100)<<"%"<<endl;