607. Sales Person

最新推荐文章于 2021-01-27 18:58:29 发布

原创最新推荐文章于 2021-01-27 18:58:29 发布 · 494 阅读

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文章标签：

#leetcode #easy #database

本文介绍了一种SQL查询方法，用于从销售员表中找出没有向特定公司进行销售的人员名单。通过使用not in子句结合多表连接，有效地过滤出了目标数据。

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Description

Given three tables: salesperson, company, orders.
Output all the names in the table salesperson, who didn’t have sales to company 'RED'.

Example
Input

Table: salesperson

+----------+------+--------+-----------------+-----------+
| sales_id | name | salary | commission_rate | hire_date |
+----------+------+--------+-----------------+-----------+
|   1      | John | 100000 |     6           | 4/1/2006  |
|   2      | Amy  | 120000 |     5           | 5/1/2010  |
|   3      | Mark | 65000  |     12          | 12/25/2008|
|   4      | Pam  | 25000  |     25          | 1/1/2005  |
|   5      | Alex | 50000  |     10          | 2/3/2007  |
+----------+------+--------+-----------------+-----------+

The table salesperson holds the salesperson information. Every salesperson has a sales_id and a name.

Table: company

+---------+--------+------------+
| com_id  |  name  |    city    |
+---------+--------+------------+
|   1     |  RED   |   Boston   |
|   2     | ORANGE |   New York |
|   3     | YELLOW |   Boston   |
|   4     | GREEN  |   Austin   |
+---------+--------+------------+

The table company holds the company information. Every company has a com_id and a name.

Table: orders

+----------+----------+---------+----------+--------+
| order_id |  date    | com_id  | sales_id | amount |
+----------+----------+---------+----------+--------+
| 1        | 1/1/2014 |    3    |    4     | 100000 |
| 2        | 2/1/2014 |    4    |    5     | 5000   |
| 3        | 3/1/2014 |    1    |    1     | 50000  |
| 4        | 4/1/2014 |    1    |    4     | 25000  |
+----------+----------+---------+----------+--------+

The table orders holds the sales record information, salesperson and customer company are represented by sales_id and com_id.

output

+------+
| name | 
+------+
| Amy  | 
| Mark | 
| Alex |
+------+

Explanation

According to order '3' and '4' in table orders, it is easy to tell only salesperson 'John' and 'Alex' have sales to company 'RED',
so we need to output all the other names in table salesperson.

select name
from salesperson
where sales_id not in
(select o.sales_id
from company c, orders o 
where c.com_id = o.com_id 
and c.name = 'red')