Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1
/ \
2 5
/ \ \
3 4 6
The flattened tree should look like:
1
\
2
\
3
\
4
\
5
\
6
Hints:
If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order traversal.
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public void flatten(TreeNode root) {
if (root == null) return;
Stack<TreeNode> stack = new Stack<TreeNode>();
stack.push(root);
TreeNode lastNode = null;
while (!stack.isEmpty()) {
TreeNode node = stack.pop();
if (lastNode != null) {
lastNode.left = null;
lastNode.right = node;
}
lastNode = node;
TreeNode left = node.left;
TreeNode right = node.right;
if (right != null) {
stack.push(right);
}
if (left != null) {
stack.push(left);
}
}
}
}
本文介绍了一种将二叉树结构通过特定算法展平为链表的方法。该方法利用栈结构进行先序遍历,使得每个节点的右子节点指向下一个遍历到的节点,最终形成链表形式。
845

被折叠的 条评论
为什么被折叠?



