练习28
# l1 = []
# for i in range(1,101):
# l1.append(i)
# print(l1)
# 列表推导式: 一行代码几乎搞定你需要的任何的列表
# 循环模式 [变量(加工后的变量) for 变量 in iterable]
# l = [ i for i in range(1,101)]
# print(l)
# l = ['python%s期' % i for i in range(1,16)]
# print(l)
# l = [i**2 for i in range(1,11)]
# print(l)
# 筛选模式 [变量(加工后的变量) for 变量 in iterable if 条件]
# l = [i for i in range(1,31) if i % 2 ==0]
# print(l)
# l = [i for i in range(31) if i%3 == 0]
# print(l)
# l = [i**2 for i in range(31) if i%3 == 0]
# print(l)
# names = [['Tom', 'Billy', 'Jefferson', 'Andrew', 'Wesley', 'Steven', 'Joe'],
# ['Alice', 'Jill', 'Ana', 'Wendy', 'Jennifer', 'Sherry', 'Eva']]
# l = [j for i in names for j in i if j.count('e')==2]
# print(l)
# 列表推导式
# 优点: 一行解决,方便
# 缺点: 容易着迷,不易排错,不能超过三次循环
# 列表推导式不能解决所有列表的问题,所以不要太可以用
# 生成器表达式: 将列表推导式的 [] 换成 () 即可
# g = (i for i in range(1000000000))
# print(g.__next__())
# print(g.__next__())
# print(g.__next__())
# print(g.__next__())
# print(g.__next__())
# 字典推导式
# mcase = {'a': 10, 'b': 34}
# mcase_frequency = {mcase[k]:k for k in mcase}
# for k in mcase:
# print(k)
# print(mcase_frequency)
# mcase = {'a': 10, 'b': 34, 'A': 7, 'Z': 3}
# mcase_frequency = {k.lower():mcase.get(k.lower(),0)+mcase.get(k.upper(),0)
# for k in mcase.keys()}
# print(mcase_frequency)
# squared = {x**2 for x in [1, -1, 2]}
# print(squared)