day6作业

1.声明一个字典保存一个学生的信息，学生信息中包括: 姓名、年龄、成绩(单科)、电话、性别(男、女、不明)

stu = {
    'name': '张三',
    'age': 18,
    'grade': 98,
    'tel': '19654545465',
    'sex': '男'}
print(stu)

2.声明一个列表，在列表中保存6个学生的信息(6个题1中的字典)

stu = {
    'students': [
        {
            'name': '张三',
            'age': 18,
            'grade': 98,
            'tel': '19654545465',
            'sex': '男'
        },
        {
            'name': '李四',
            'age': 19,
            'grade': 99,
            'tel': '19654545468',
            'sex': '男'
        },
        {
            'name': '小花',
            'age': 17,
            'grade': 95,
            'tel': '19654545467',
            'sex': '女'
        },
        {
            'name': '小明',
            'age': 20,
            'grade': 48,
            'tel': '19655545466',
            'sex': '男'
        },
        {
            'name': '小C',
            'age': 21,
            'grade': 70,
            'tel': '19655545465',
            'sex': '男'
        },
        {
            'name': '小岚',
            'age': 23,
            'grade': 58,
            'tel': '19655545468',
            'sex': '不明'
        },
    ]
}

​ a.统计不及格学生的个数

count = 0
for i in stu['students']:
    if i['grade'] < 60:
        count += 1
print(count)

​ b.打印不及格学生的名字和对应的成绩

for i in stu['students']:
    if i['grade'] < 60:
        print(i['name'], i['grade'])

​ c.统计未成年学生的个数

count = 0
for i in stu['students']:
    if i['age'] < 18:
        count += 1
print(count)

​ d.打印手机尾号是8的学生的名字

for i in stu['students']:
    if str(i['tel'])[-1:-2:-1] == '8':
        print(i['name'])

​ e.打印最高分和对应的学生的名字

max_grade = 0
for i in stu['students']:
    if i['grade'] > max_grade:
        max_grade = i['grade']
print('最高分：', max_grade)
for name in stu['students']:
    if name['grade'] == max_grade:
        print('获得最高分的学生：', name['name'])

​ f.将列表按学生成绩从大到小排序(挣扎一下，不行就放弃)

​ g.删除性别不明的所有学生

for i in stu['students'][:]:
    if i['sex'] == '不明':
        i.clear()
print(stu)

3.用三个列表表示三门学科的选课学生姓名(一个学生可以同时选多门课)

subject = {
    '计算机网络': ['张三', '李四', '小王'],
    '数据结构': ['小王', '小张'],
    'Python': ['张三', '小兰']
}

​ a. 求选课学生总共有多少人

people = []
for i in subject['计算机网络']:
    people.append(i)
for j in subject['数据结构']:
    people.append(j)
for k in subject['Python']:
    people.append(k)
new = []
for i in people:
    if i not in new:
        new.append(i)
print(len(new))

b. 求只选了第一个学科的人的数量和对应的名字

network = []
structure = []
python = []
count = 0
for i in subject['计算机网络']:
    network.append(i)
for j in subject['数据结构']:
    structure.append(j)
for k in subject['Python']:
    python.append(k)
for i in network:
    if i not in structure and i not in python:
        count += 1
        print(i)
print(count)

​ c. 求只选了一门学科的学生的数量和对应的名字

network = []
structure = []
python = []
for i in subject['计算机网络']:
    network.append(i)
for j in subject['数据结构']:
    structure.append(j)
for k in subject['Python']:
    python.append(k)
count = 0
for i in network:
    if i not in structure and i not in python:
        count += 1
        print(i)
for j in structure:
    if j not in python and j not in network:
        count += 1
        print(j)
for k in python:
    if k not in network and k not in structure:
        count += 1
        print(k)
print(count)

d. 求只选了两门学科的学生的数量和对应的名字

network = []
structure = []
python = []
for i in subject['计算机网络']:
    network.append(i)
for j in subject['数据结构']:
    structure.append(j)
for k in subject['Python']:
    python.append(k)
count = 0
for i in network:
    if i in structure  and i not in python or i not in structure and i in python:
        count += 1
        print(i)
for j in structure:
    if j in network and j not in python or j not in network and j in python:
        count += 1
        print(j)
for k in python:
    if k in network and k not in structure or k not in network and k in structure:
        count += 1
        print(k)
print(count)

​ e. 求选了三门学生的学生的数量和对应的名字

network = []
structure = []
python = []
count = 0
for i in subject['计算机网络']:
    network.append(i)
for j in subject['数据结构']:
    structure.append(j)
for k in subject['Python']:
    python.append(k)
for i in network:
    if i in structure and i in python:
        count += 1
        print(i)
for j in structure:
    if j in network and j in python:
        count += 1
        print(j)
for k in python:
    if k in network and k in structure:
        count += 1
        print(k)
print(count)