BUG调试: Jump to the invalid address stated on the next line at 0x0: ???

gdb或者vlagrind报告：

==14569== Jump to the invalid address stated on the next line
==14569==    at 0x0: ???
==14569==  Address 0x0 is not stack'd, malloc'd or (recently) free'd

 错误原因：函数通过jmp,call,ret等指令跳转到0x00，错误可能出现的范围

1.函数缓冲区溢出覆盖了返回地址，然后又调用了return，例如

#include <memory.h>

void main(void)
{
	int i;
	memset(&i,0,20);
	return;
}

 2.函数使用了未初始化的函数指针，例如

void (*func)(void);

void main(void)
{
	func();
}

 

转载于:https://www.cnblogs.com/codingMozart/p/4791141.html