189.Rotate Array

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本文深入探讨了数组旋转问题，提供了一种通过从右往左移动元素来实现数组向右旋转k步的有效解决方案。示例展示了如何将输入数组[1,2,3,4,5,6,7]在k=3的情况下，经过三次旋转得到输出数组[5,6,7,1,2,3,4]。此外，还讨论了一个包含负数的数组[-1,-100,3,99]在k=2时的旋转过程。文章挑战读者思考更多可能的解决方案，并提出了在不使用额外空间的情况下进行原地操作的优化目标。

Given an array, rotate the array to the right by k steps, where k is non-negative.

Example 1:

Input: [1,2,3,4,5,6,7] and k = 3
Output: [5,6,7,1,2,3,4]
Explanation:
rotate 1 steps to the right: [7,1,2,3,4,5,6]
rotate 2 steps to the right: [6,7,1,2,3,4,5]
rotate 3 steps to the right: [5,6,7,1,2,3,4]

Example 2:

Input: [-1,-100,3,99] and k = 2
Output: [3,99,-1,-100]
Explanation: 
rotate 1 steps to the right: [99,-1,-100,3]
rotate 2 steps to the right: [3,99,-1,-100]

Note:

Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
Could you do it in-place with O(1) extra space?

解决思路：从右往左移动。

/**
 * @param {number[]} nums
 * @param {number} k
 * @return {void} Do not return anything, modify nums in-place instead.
 */
var rotate = function(nums, k) {
	let x = 0;
	while (x < k) {
		let c = nums.pop();
		nums.unshift(c);
		x++;
	}
};