代码:
#include <iostream>
using namespace std;
class Base
{
public:
Base(char i)
{
cout<<"Base constructor. --"<<i<<endl;
}
};
class Derived1:virtual public Base
{
public:
Derived1(char i,char j):Base(i)
{
cout<<"Derived1 constructor. --"<<j<<endl;
}
};
class Derived2:virtual public Base
{
public:
Derived2(char i,char j):Base(i)
{
cout<<"Derived2 constructor. --"<<j<<endl;
}
};
class MyDerived:public Derived1,public Derived2
{
public:
MyDerived(char i,char j,char k,char l,char m,char n,char x): Derived2(i,j), Derived1(k,l), Base(m), d(n)
{
cout<<"MyDerived constructor. --"<<x<<endl;
}
private:
Base d;
};
int main()
{
MyDerived obj('A','B','C','D','E','F','G');
return 0;
}
运行结果:
学习心得:
声明Base为公有继承的虚基类,而MyDerived为Derived1和Derived2的派生类,系统只执行最后的派生类对虚基类的构造函数的调用,所以Base类的数据成员不会被多次初始化。
本文深入探讨了C++中使用虚基类时,多重虚继承构造函数的执行顺序及对基类数据成员的影响,揭示了系统如何仅执行最后一个派生类对虚基类的构造函数调用,避免了数据成员的重复初始化。
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