Scientific notation is the way that scientists easily handle very large numbers or very small numbers. The notation matches the regular expression [+-][1-9]"."[0-9]+E[+-][0-9]+ which means that the integer portion has exactly one digit, there is at least one
digit in the fractional portion, and the number and its exponent's signs are always provided even when they are positive.
Now given a real number A in scientific notation, you are supposed to print A in the conventional notation while keeping all the significant figures.
Input Specification:
Each input file contains one test case. For each case, there is one line containing the real number A in scientific notation. The number is no more than 9999 bytes in length and the exponent's absolute value is no more than 9999.
Output Specification:
For each test case, print in one line the input number A in the conventional notation, with all the significant figures kept, including trailing zeros,
Sample Input 1:
+1.23400E-03
Sample Output 1:
0.00123400
Sample Input 2:
-1.2E+10
Sample Output 2:
Now given a real number A in scientific notation, you are supposed to print A in the conventional notation while keeping all the significant figures.
Input Specification:
Each input file contains one test case. For each case, there is one line containing the real number A in scientific notation. The number is no more than 9999 bytes in length and the exponent's absolute value is no more than 9999.
Output Specification:
For each test case, print in one line the input number A in the conventional notation, with all the significant figures kept, including trailing zeros,
Sample Input 1:
+1.23400E-03
Sample Output 1:
0.00123400
Sample Input 2:
-1.2E+10
Sample Output 2:
-12000000000
IDEA
1.利用string函数将找到E的位置,分别确定其底数coff,指数exps,将exps转为整数型exp
2.分exp正负情况考虑
exp为负:先在小数点后补足够的0,在写原数
exp为正:想写原数,注意小数点位置,有必要还要在后边补0
CODE
#include<iostream>
#include<cstring>
#include<sstream>
#include<fstream>
using namespace std;
int main(){
#ifndef ONLINE_JUDGE
freopen("input.txt","r",stdin);
#endif
string A;
while(cin>>A){
int index=A.find('E');
string coff=A.substr(1,index-1);
string exps=A.substr(index+1);
stringstream ss;
int exp;
ss<<exps;
ss>>exp;
if(A[0]=='-'){
cout<<"-";
}
if(exp<0){
exp=-exp;
cout<<"0.";
int i;
for(i=1;i<exp;i++){
cout<<"0";
}
for(i=0;i<coff.size();i++){
if(coff[i]!='.'){
cout<<coff[i];
}
}
cout<<endl;
}else{
cout<<coff[0];
int count=0;
for(int i=2;i<coff.size();i++){
cout<<coff[i];
count++;
if(count==exp&&exp<coff.size()-2){
cout<<".";
}
}
for(int i=count;i<exp;i++){
cout<<"0";
}
cout<<endl;
}
}
#ifndef ONLINE_JUDGE
fclose(stdin);
#endif
return 0;
}