1073. Scientific Notation (20)

本文介绍了一种将科学计数法表示的数字转换为常规计数法的方法,并提供了一个具体的编程实现方案。该方案能够处理非常大或非常小的数字,并保持所有有效数字。

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Scientific notation is the way that scientists easily handle very large numbers or very small numbers. The notation matches the regular expression [+-][1-9]"."[0-9]+E[+-][0-9]+ which means that the integer portion has exactly one digit, there is at least one digit in the fractional portion, and the number and its exponent's signs are always provided even when they are positive.

Now given a real number A in scientific notation, you are supposed to print A in the conventional notation while keeping all the significant figures.

Input Specification:

Each input file contains one test case. For each case, there is one line containing the real number A in scientific notation. The number is no more than 9999 bytes in length and the exponent's absolute value is no more than 9999.

Output Specification:

For each test case, print in one line the input number A in the conventional notation, with all the significant figures kept, including trailing zeros,

Sample Input 1:
+1.23400E-03
Sample Output 1:
0.00123400
Sample Input 2:
-1.2E+10
Sample Output 2:

-12000000000


IDEA

1.利用string函数将找到E的位置,分别确定其底数coff,指数exps,将exps转为整数型exp

2.分exp正负情况考虑

exp为负:先在小数点后补足够的0,在写原数

exp为正:想写原数,注意小数点位置,有必要还要在后边补0


CODE

#include<iostream>
#include<cstring>
#include<sstream> 
#include<fstream>
using namespace std;
int main(){
	#ifndef ONLINE_JUDGE
	freopen("input.txt","r",stdin);
	#endif
	
	string A;
	while(cin>>A){
		int index=A.find('E');
		string coff=A.substr(1,index-1);
		string exps=A.substr(index+1);
		stringstream ss;
		int exp;
		ss<<exps;
		ss>>exp;
		
		if(A[0]=='-'){
			cout<<"-";
		}
		if(exp<0){
			exp=-exp;
			cout<<"0.";
			int i;
			for(i=1;i<exp;i++){
				cout<<"0";
			}
			for(i=0;i<coff.size();i++){
				if(coff[i]!='.'){
					cout<<coff[i];
				}
			}
			cout<<endl;
		}else{
			cout<<coff[0];
			int count=0;
			for(int i=2;i<coff.size();i++){
				cout<<coff[i];
				count++;
				if(count==exp&&exp<coff.size()-2){
					cout<<".";
				}
			}
			for(int i=count;i<exp;i++){
				cout<<"0";
			}			
			cout<<endl;
		}
	}
	
	#ifndef ONLINE_JUDGE
	fclose(stdin);
	#endif
	return 0;
}




                
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