平时使用 memset 函数都是用来初始化字符串,从来没有注意过它具体是怎么实现的,最近无意中发现原来这个函数里面还是有坑的。
我尝试用它来初始化整型数组
int array[10];
memset(array, 1, sizeof(a));
我原本是想将数组元素全部初始化为1,可是却是这样的:

一开始不明白为什么会这样,查了以后才知道,void *memset(void *s, int ch, size_t n) 并不是直接把 ch 的
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平时使用 memset 函数都是用来初始化字符串,从来没有注意过它具体是怎么实现的,最近无意中发现原来这个函数里面还是有坑的。
我尝试用它来初始化整型数组
int array[10];
memset(array, 1, sizeof(a));
我原本是想将数组元素全部初始化为1,可是却是这样的:

一开始不明白为什么会这样,查了以后才知道,void *memset(void *s, int ch, size_t n) 并不是直接把 ch 的
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nn.output = 'softmax'; % use softmax outputopts.numepochs = 5; % Number of full sweeps through dataopts.batchsize = 1000; % Take a mean gradient step over this many samplesopts.plot = 1; % enable plottingnn = nntrain(nn, tx, ty, opts, vx, vy); % nntrain takes validation set as last two arguments (optionally)[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');```[](https://bitdeli.com/free "Bitdeli Badge")
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