warning C6302: Format string mismatch: character string passed as parameter '4' when wide character

LPCWSTR char2LPCWSTR(char* c_temp, WCHAR* temp /*= temp_wchar */)
{
 wmemset(temp, 0, MAX_PATH);

 swprintf_s(temp, MAX_PATH, L"%s", c_temp);

 return temp;
}

报了个warning  查msdn如下：

 

 

warning C6302: format string mismatch: character string passed as parameter <number> when wide character string is required in call to <function>

This warning indicates that the format string specifies that a wide character string is required. However, a character string is being passed. This defect is likely to cause a crash or a corruption of some form.

Example

---

The following sample code generates this warning because a character string is passed to wprintf function:

View Colorized Copy to Clipboard Print

#include<stdio.h>
  
  void f()
  {
    char buff[5] = "hi";
  
    wprintf(L"%s", buff);
  }
  

#include<stdio.h>

void f()
{
  char buff[5] = "hi";

  wprintf(L"%s", buff);
}

The following sample code uses %hs to specify a single-byte character string with wprintf function:

View Colorized Copy to Clipboard Print

#include<stdio.h>
  
  void f()
  {
    char buff[5] = "hi";
  
    wprintf(L"%hs", buff);
  }
  

#include<stdio.h>

void f()
{
  char buff[5] = "hi";

  wprintf(L"%hs", buff);
}

The following sample code uses safe string manipulation function wprintf_s to correct this warning:

View Colorized Copy to Clipboard Print

#include<stdio.h>
  
  void f()
  {
    char buff[5] = "hi";
  
    wprintf_s(L"%hs", buff);
  }
  

总结 ： 使用安全函数wprintf_s 指定格式为%hs就OK