Given an array and a value, remove all instances of that value in place and return the new length.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
#include<iostream>
#include<vector>
using namespace std;
int removeElement(int A[], int n, int elem) {
int newlength = 0;
for (int i = 0; i < n;++i)
{
if (A[i] != elem)
{
A[newlength] = A[i];
newlength++;
}
}
return newlength;
}
本文介绍了一种在数组中移除特定值并返回新长度的算法实现。该算法通过遍历数组并忽略指定值的方式,有效地实现了原地修改,简化了数组处理流程。
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