!!!argc and argv as parameter of main function_parameter and argv-优快云博客

本文详细介绍了C/C++中如何通过main函数接收并处理命令行参数。具体包括argc和argv变量的作用及使用方法，并给出一个实际示例程序来展示如何打印所有传入的参数。

`Definition`

http://stackoverflow.com/questions/3024197/what-does-int-argc-char-argv-mean

argv and argc are how command line arguments are passed tomain() in C and C++.

argc will be the number of strings pointed to by argv. This will (in practice) be 1 plus the number of arguments, as virtually all implementations will prepend the name of the program to the array.

The variables are named argc (argument count) and argv (argument vector) by convention, but they can be given any valid identifier:int main(int num_args, char** arg_strings) is equally valid.

They can also be omitted entirely, yielding int main(), if you do not intend to process command line arguments.

Practice

#include <stdlib.h>

int main(int argc, char* argv[])
{
    printf("Have %d arguments", argc);
    for (int i = 0; i<argc; ++i) {
        printf("%s \n", argv[i]);
    }
}

Provide arguments: a1 b2 c3

output is:

Have 4 arguments 
./Test               // the full path to the Test project
dsfds 
sdf 
3 
Program ended with exit code: 0

How to provide these parameters in Xcode

http://stackoverflow.com/questions/1454587/passing-arguments-to-main-function