Leetcode: Length of Last Word

最新推荐文章于 2018-07-17 23:20:16 发布

原创最新推荐文章于 2018-07-17 23:20:16 发布 · 371 阅读

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本文将介绍如何使用Python处理字符串，专注于提取并计算给定字符串中最后一个单词的长度。通过使用split()方法，我们可以高效地解决这类问题。

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Question

Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = “Hello World”,
return 5.

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Analysis

Solution

Mistake taken

The first thought is use string.split(), and return s[-1]. However, there maybe multiple ” ” at the end of string.

Code

class Solution:
    # @param {string} s
    # @return {integer}
    def lengthOfLastWord(self, s):
        if s==" ":
            return 0

        s = s.split(" ")
        for i in range(len(s)-1,-1,-1):
            if len(s[i])>0:
                return len(s[i])

        return 0