XSL中如何接收到XML地址中URL查询字符串传递的参数?
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"xmlns:msxsl="urn:schemas-microsoft-com:xslt"xmlns:user="whatever"><![CDATA[ function getDocURL(nodelist,sNa
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2004-09-06 11:13:00 ·
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