python_day3

from random import randint
num = 0
verify_code = ""
while num < 4:
    verify_code += chr(randint(65,90))
    num += 1
print(verify_code)
c = 1
while c <= 3:
    user_name = input("账号")
    password = input("密码")
    code = input("验证码")
    if code == verify_code:
        if user_name == "adm" and password == "123":
            print("登陆成功")
            break
        elif user_name != "adm" and password != "123":
            print("你还有%d次机会" % (3-c))
            c += 1
            continue
    else:
        print("验证码错误,你还有三次机会")
        continue
#要求

  1. 系统调动成4位随机数. 作为登录验证码.
  2. 用户输入用户名和密码还有验证码. 
  3. 用户可以有三次登录的机会. 但是验证码如果输入错误. 不计算在内.

转载于:https://www.cnblogs.com/lowen107/p/9822212.html