C语言实现：万年历

最新推荐文章于 2022-04-26 16:06:24 发布

六六哥

最新推荐文章于 2022-04-26 16:06:24 发布

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文章标签：语言 c sun 日历

本文链接：https://blog.youkuaiyun.com/eric_liufeng/article/details/5847101

本文分享了一个使用C语言编写的万年历程序，可以打印任意年份的日历。程序包括了月份天数的定义、判断闰年的函数、获取年份某一天为星期几的函数以及打印日历的函数。用户可以通过输入年份来查看对应年份的日历。

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经过近这几天的努力，终于写完了这个"万年历"的程序了，共享一下, 特别是同"勉"共享

[需求]

请打印出任意年份的日历

[代码]

#include <stdio.h> #define LMonth 31 #define SMonth 30 #define VMonth 28 typedef enum { Sun, Mon, Jue, Wed, Thu, Fri, Sat } WEEK; typedef enum { January = 1, February, Match, Apirl, May, June, July, August, September, October, November, December } MONTH; void printMonHead(void) { printf(" Sun Mon Jue Wed Thu Fri Sat/n"); } void printMonth(const WEEK firstDay, int length ) { WEEK weekDay = firstDay % 7; int i; printMonHead(); for (i=0; i<weekDay;++i) { printf(" "); } for(i=1;i<=length;++i) { weekDay = (++weekDay)%7; printf("%7d", i); if(weekDay==0) printf("/n"); } printf("/n"); } int isLeapYear(const int yr) { return ( yr%( yr%100 ? 4:400) ? 0 : 1); } int getYearDay(const int year) { int lastYear = year-1; int yearNum = lastYear-1899; int walker,counter=0; for(walker=1900; walker < year; ++walker) { if(isLeapYear(walker)==1) ++counter; } return (365*yearNum+counter+1)%7; } void printYear(const int y) { WEEK yDay = getYearDay(y); int vDay = isLeapYear(y); int monWeeks[13]; int monLen [13]; monLen[0]=0; monLen[January]=31; monLen[February]=28+vDay; monLen[Match]=31; monLen[Apirl]=30; monLen[May]=31; monLen[June]=30; monLen[July]=31; monLen[August]=31; monLen[September]=30; monLen[October]=31; monLen[November]=30; monLen[December]=31; monWeeks[0]=0; monWeeks[January] = yDay; monWeeks[February] = ((monWeeks[January] +monLen[January] )%7); monWeeks[Match] = ((monWeeks[February] +monLen[February] )%7); monWeeks[Apirl] = ((monWeeks[Match] +monLen[Match] )%7); monWeeks[May] = ((monWeeks[Apirl] +monLen[Apirl] )%7); monWeeks[June] = ((monWeeks[May] +monLen[May] )%7); monWeeks[July] = ((monWeeks[June] +monLen[June] )%7); monWeeks[August] = ((monWeeks[July] +monLen[July] )%7); monWeeks[September] = ((monWeeks[August] +monLen[August] )%7); monWeeks[October] = ((monWeeks[September] +monLen[September] )%7); monWeeks[November] = ((monWeeks[October] +monLen[October] )%7); monWeeks[December] = ((monWeeks[November] +monLen[November] )%7); int i; for(i=January; i<=December; ++i) { printf("/n-------------------------------------------------/n"); printf(" %d, %d /n",y,i); printf("-------------------------------------------------/n"); printMonth(monWeeks[i],monLen[i]); printf("/n"); } return; } int main(void) { // int y3 = 2000; // int y3 = 1946; // printYear(y3); int y; int quit=0; do { printf("Please enter which Year to Print For You (0 to quit): "); scanf("%d",&y); printf("/n"); if(y==0) quit = 1; else printYear(y); }while(!quit); return 0; }

输出

Please enter which Year to Print For You (0 to quit): 1973

-------------------------------------------------

1946, 1

-------------------------------------------------

Sun Mon Jue Wed Thu Fri Sat

1 2 3 4 5

6 7 8 9 10 11 12

13 14 15 16 17 18 19

20 21 22 23 24 25 26

27 28 29 30 31

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