快速排序的实现--挖坑法

//*********************挖坑法(快排的一种实现方式)************************

int PartSort(int *a, intleft, intright)

{

                 int key = a [right];

                 int begin = left ;

                 int end = right ;

                 while (begin < end)

                {

                                 while (begin < end && a [begin] <= key) //begin找比key大的

                                                begin++;

                                 if (begin < end)      //找到且begin < end则把begin的值给end，begin成为新的坑

                                                 a[end] = a [begin];

                                 while (begin < end && a [end] >= key)  //end找比key小的

                                                end--;

                                 if (begin < end)    //找到且begin < end则把end的值给begin，end成为新的坑

                                                 a[begin] = a [end];

                }

                 //出了循环：end可能和begin指向同一个，把key的值给begin或者end都可以

                 //          end比begin小，则begin的位置一定是key的位置

                 //此处不做判断，所以直接把key的值给a[begin]

                 a[begin] = key;

                 return begin;

}

void DigHoles(int *a, int left, int right)

{

                 assert(a );

                 if (left >= right)

                                 return;

                 int mid = PartSort(a , left, right);

                DigHoles( a, left , mid - 1);

                DigHoles( a, mid + 1, right );

}

void DigHolesTest()

{

                                    //int arr[] = { 2, 0, 4, 9, 3, 6, 8, 7, 1, 5 };

                                    int arr[] = { 2, 5, 4, 9, 3, 5, 8, 7, 1, 5 };

                                                 int _size = sizeof (arr) / sizeof(arr[0]);

                                                DigHoles(arr, 0, _size - 1);

                                                Print(arr, _size);

}