同一个事务内修改两次，第二次改回原状会不会产生binlog，改前改后相同会不会产生binlog

最新推荐文章于 2025-01-07 16:50:25 发布

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最新推荐文章于 2025-01-07 16:50:25 发布

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分类专栏： MySQL

本文链接：https://blog.youkuaiyun.com/arkblue/article/details/46402403

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实验一

1 修改前表内容

mysql> select * from user;
+----------------------------+------+------------+-------+-------+
| gmt_create                 | name | gmt_modify | gmt_4 | gmt_3 |
+----------------------------+------+------------+-------+-------+
| 2015-12-12 12:12:12.000000 | aaa  | NULL       | NULL  | NULL  |
+----------------------------+------+------------+-------+-------+
1 row in set (0.00 sec)

show master status; 的结果，位点是 1655；

mysql> show master status;
+------------------+----------+--------------+------------------+-------------------+
| File             | Position | Binlog_Do_DB | Binlog_Ignore_DB | Executed_Gtid_Set |
+------------------+----------+--------------+------------------+-------------------+
| mysql-bin.000061 |     1655 |              |                  |                   |
+------------------+----------+--------------+------------------+-------------------+
1 row in set (0.00 sec)

2 执行update操作，但是改前改后的值相同

conn.setAutoCommit(false);
Statement stmt = conn.createStatement();
String sqlDiff = "update user.user set name='aaa';";
stmt.execute(sqlDiff);
conn.commit();

3 执行后执行show master status；结果没有变化-- 说明并没有产生binlog

mysql> show master status;
+------------------+----------+--------------+------------------+-------------------+
| File             | Position | Binlog_Do_DB | Binlog_Ignore_DB | Executed_Gtid_Set |
+------------------+----------+--------------+------------------+-------------------+
| mysql-bin.000061 |     1655 |              |                  |                   |
+------------------+----------+--------------+------------------+-------------------+
1 row in set (0.00 sec)

实验二

1 和实验一相同

2 执行脚本

conn.setAutoCommit(false);
Statement stmt = conn.createStatement();
String sqlSame = "update user.user set name='ccc';";
String sqlDiff = "update user.user set name='aaa';";
stmt.execute(sqlSame);
stmt.execute(sqlDiff);

3 在mysql上执行show master status， binlog的位点发生了变化，从1655变成1968

mysql> show master status;
+------------------+----------+--------------+------------------+-------------------+
| File             | Position | Binlog_Do_DB | Binlog_Ignore_DB | Executed_Gtid_Set |
+------------------+----------+--------------+------------------+-------------------+
| mysql-bin.000061 |     1968 |              |                  |                   |
+------------------+----------+--------------+------------------+-------------------+
1 row in set (0.00 sec)

4 执行mysqlbinlog工具，查看binlog文件内容

mysqlbinlog --host 127.0.0.1  -P3306 -R -uroot   -proot  mysql-bin.000061 -j 4 --base64-output=decode-rows --verbose

查看结果，产生的两次变更都记录到binlog里面。