public ActionResult tb()
{
ArrayList list = new ArrayList();
list.Add(stufile);
return new ContentResult
{
Content = new JavaScriptSerializer { MaxJsonLength = Int32.MaxValue }.Serialize(list),
ContentType = "application/json"
};
public class stuReadFile
{
public string file_name;
public string belong;
public string size;
public string create_time;
public string fpath;
}
list<t>转为json
最新推荐文章于 2023-03-23 17:29:42 发布