[other]成功申请到WEB2MESSENGER!

作者分享了终于通过一位未具名朋友的邀请成功加入期待已久的平台的喜悦之情,并提及该平台的作用众所周知,值得庆祝。
早就听说它了,今天才申请到,还感谢一位不知名的朋友给我发的邀请!
效果:
Yakeir.png

它有什么作用,我想就不用说了,大家都这么熟悉!

值得庆贺,呵呵~~

转载于:https://www.cnblogs.com/yang_sy/archive/2005/11/04/268774.html

内容概要:本文详细介绍了“秒杀商城”微服务架构的设计与实战全过程,涵盖系统从需求分析、服务拆分、技术选型到核心功能开发、分布式事务处理、容器化部署及监控链路追踪的完整流程。重点解决了高并发场景下的超卖问题,采用Redis预减库存、消息队列削峰、数据库乐观锁等手段保障数据一致性,并通过Nacos实现服务注册发现与配置管理,利用Seata处理跨服务分布式事务,结合RabbitMQ实现异步下单,提升系统吞吐能力。同时,项目支持Docker Compose快速部署和Kubernetes生产级编排,集成Sleuth+Zipkin链路追踪与Prometheus+Grafana监控体系,构建可观测性强的微服务系统。; 适合人群:具备Java基础和Spring Boot开发经验,熟悉微服务基本概念的中高级研发人员,尤其是希望深入理解高并发系统设计、分布式事务、服务治理等核心技术的开发者;适合工作2-5年、有志于转型微服务或提升架构能力的工程师; 使用场景及目标:①学习如何基于Spring Cloud Alibaba构建完整的微服务项目;②掌握秒杀场景下高并发、超卖控制、异步化、削峰填谷等关键技术方案;③实践分布式事务(Seata)、服务熔断降级、链路追踪、统一配置中心等企业级中间件的应用;④完成从本地开发到容器化部署的全流程落地; 阅读建议:建议按照文档提供的七个阶段循序渐进地动手实践,重点关注秒杀流程设计、服务间通信机制、分布式事务实现和系统性能优化部分,结合代码调试与监控工具深入理解各组件协作原理,真正掌握高并发微服务系统的构建能力。
### Meaning 'Other web broswer will be denied!' means that access from web browsers other than a specified or approved one will not be allowed. For example, a website might be configured to only work properly with a particular browser (such as Chrome), and if a user tries to access it using Firefox, Safari, or other browsers, they will be blocked or denied access. ### Solutions - **Use the recommended browser**: Check if the website or application provides information about the recommended browser. Then download and install that browser, and access the content again. For example, if the website suggests using Chrome, go to the official Chrome website to download and install it. - **Check browser compatibility settings**: Some websites use features that are only supported by certain browsers or versions. You can try to update your current browser to the latest version, as new versions often come with better compatibility. In some browsers, you can also try to enable compatibility mode. For Internet Explorer, you can click on the gear icon and select "Compatibility View settings". - **Contact the website administrator**: If the above methods do not work, you can try to contact the administrator of the website. Provide them with details about the browser you are using, the error message you are getting, and the steps you have taken. They may be able to adjust the website settings to allow access from your browser. ```python # Here is a simple example of using the requests library to simulate accessing a website with a specific browser header import requests url = 'https://example.com' # Replace with the actual website URL headers = { 'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.124 Safari/537.36' } try: response = requests.get(url, headers=headers) print(response.text) except requests.RequestException as e: print(f"An error occurred: {e}") ```
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