【cf492】D. Vanya and Computer Game(二分)

本文解析了Codeforces竞赛中一道关于二分查找和攻击频率的问题。通过二分查找确定击溃怪物所需时间,判断最后一下攻击是由Vanya、Vova还是两人同时完成。

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http://codeforces.com/contest/492/problem/D

有时候感觉人sb还是sb,为什么题目都看不清楚?

x per second, y per second...

于是我们二分second即可。

而且对每个monster都有伤害。。。。

#include <cstdio>
#include <cstring>
#include <cmath>
#include <string>
#include <iostream>
#include <algorithm>
#include <queue>
#include <set>
#include <map>
using namespace std;
typedef long long ll;
#define rep(i, n) for(int i=0; i<(n); ++i)
#define for1(i,a,n) for(int i=(a);i<=(n);++i)
#define for2(i,a,n) for(int i=(a);i<(n);++i)
#define for3(i,a,n) for(int i=(a);i>=(n);--i)
#define for4(i,a,n) for(int i=(a);i>(n);--i)
#define CC(i,a) memset(i,a,sizeof(i))
#define read(a) a=getint()
#define print(a) printf("%d", a)
#define dbg(x) cout << (#x) << " = " << (x) << endl
#define error(x) (!(x)?puts("error"):0)
#define rdm(x, i) for(int i=ihead[x]; i; i=e[i].next)
inline const int getint() { int r=0, k=1; char c=getchar(); for(; c<'0'||c>'9'; c=getchar()) if(c=='-') k=-1; for(; c>='0'&&c<='9'; c=getchar()) r=r*10+c-'0'; return k*r; }


int main() {
	int n; ll x, y;
	read(n); read(x); read(y);
	for1(i, 1, n) {
		ll a=getint();
		ll l=0, r=1ll<<60, mid;
		while(l<=r) {
			mid=(l+r)>>1;
			if(mid/x+mid/y>=a) r=mid-1;
			else l=mid+1;
		}
		mid=r+1;
		if(mid%x==0 && mid%y==0) puts("Both");
		else if(mid%y==0) puts("Vanya");
		else if(mid%x==0) puts("Vova");
	}
	return 0;
}

  

 


 

 

Vanya and his friend Vova play a computer game where they need to destroy n monsters to pass a level. Vanya's character performs attack with frequency x hits per second and Vova's character performs attack with frequencyy hits per second. Each character spends fixed time to raise a weapon and then he hits (the time to raise the weapon is 1 / x seconds for the first character and 1 / y seconds for the second one). The i-th monster dies after he receives ai hits.

Vanya and Vova wonder who makes the last hit on each monster. If Vanya and Vova make the last hit at the same time, we assume that both of them have made the last hit.

Input

The first line contains three integers n,x,y (1 ≤ n ≤ 105, 1 ≤ x, y ≤ 106) — the number of monsters, the frequency of Vanya's and Vova's attack, correspondingly.

Next n lines contain integers ai (1 ≤ ai ≤ 109) — the number of hits needed do destroy the i-th monster.

Output

Print n lines. In the i-th line print word "Vanya", if the last hit on the i-th monster was performed by Vanya, "Vova", if Vova performed the last hit, or "Both", if both boys performed it at the same time.

Sample test(s)
input
4 3 2
1
2
3
4
output
Vanya
Vova
Vanya
Both
input
2 1 1
1
2
output
Both
Both
Note

In the first sample Vanya makes the first hit at time 1 / 3, Vova makes the second hit at time 1 / 2, Vanya makes the third hit at time 2 / 3, and both boys make the fourth and fifth hit simultaneously at the time 1.

In the second sample Vanya and Vova make the first and second hit simultaneously at time 1.

转载于:https://www.cnblogs.com/iwtwiioi/p/4136445.html

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