m n进制转换

#include<cstdio>
#include<cstdlib>
#include<math.h>
#include"string.h"
bool zero(long long *a,int len)
{ 
    bool zero=true;
    for(int i=0;i<len;i++)
        if(a[i]!=0) zero=false;
        return zero;
}
int main()
{
    //freopen("in.txt","r",stdin);
    int i,j,k,max,a,b,tenleft,len;
    char num[1000];
    long long n[1000], ten[1000],x[1000];
    while(scanf("%d %d",&a,&b)!=EOF)
    { 
        scanf("%s",num);
        memset(n,0,sizeof(n));
        memset(x,0,sizeof(x));
        len=strlen(num);
        for(i=0;i<len;i++)
            if(num[i]<='9'&&num[i]>='0') n[i]=num[i]-'0';
            else n[i]=num[i]-'A'+10;
            if(zero(n,len))
            {
                printf("0\n");
                continue;
            }
            j=0;
        while(!zero(n,len))
        {   
            tenleft=0;
            for(i=0;i<len;i++)
            {
                tenleft*=a;
                n[i]+=tenleft;
                tenleft=n[i]%10;
                n[i]/=10;
            }
            ten[j++]=tenleft;
        }
        /*for(i=0;i<j;i++)
        if(x[i]<=9&&x[i]>=0)
            printf("%d",ten[i]);
        else printf("%c",x[i]+'a'-10);
        printf("\n");*/
 
        len=j;
        j=0;
        while(!zero(ten,len))
        {   
            tenleft=0;
            for(i=len-1;i>=0;i--)
            {
                tenleft*=10;
                ten[i]+=tenleft;
                tenleft=ten[i]%b;
                ten[i]/=b;
            }
            x[j++]=tenleft;
        }
        for(i=j-1;i>=0;i--)
        if(x[i]<=9&&x[i]>=0)
            printf("%d",x[i]);
        else printf("%c",x[i]+'a'-10);
        printf("\n");
 
 
    }
    return 0;
}
/**************************************************************
    Problem: 1080
    User: huashiyiqike
    Language: C++
    Result: Accepted
    Time:280 ms
    Memory:1012 kb
*******************

 

转载于:https://www.cnblogs.com/huashiyiqike/articles/2878516.html