LEETCODE: Best Time to Buy and Sell Stock II

本文介绍了一种股票交易算法,允许在不同时段进行多次买卖操作,以最大化利润。通过分析每日股票价格,算法在价格上涨时买入并在价格下跌时卖出,从而实现利润最大化。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Say you have an array for which the ith element is the price of a given stock on day i.

Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).

熟能生巧,还是这题太简单了呢!


class Solution {
public:
    int maxProfit(vector<int> &prices) {
        int profits = 0;
        for(int ii = 1; ii < prices.size(); ii ++) {
            if(prices[ii] > prices[ii - 1]) {
                profits += prices[ii] - prices[ii - 1];
            }
        }
        return profits;
    }
};


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值