LEETCODE: Merge Sorted Array

最新推荐文章于 2021-10-23 14:47:57 发布

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最新推荐文章于 2021-10-23 14:47:57 发布

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文章标签： LEETCODE 算法数组

本文链接：https://blog.youkuaiyun.com/anyicheng2015/article/details/42193455

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本文介绍了一种将两个已排序的整数数组B合并到数组A中并保持排序的方法。该算法通过遍历数组B并将每个元素插入到数组A的适当位置来实现。详细展示了如何调整数组A的空间以容纳额外的元素。

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Given two sorted integer arrays A and B, merge B into A as one sorted array.

Note:
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are mand n respectively.

class Solution {
public:
    void merge(int A[], int m, int B[], int n) {
        for(int ii = 0; ii < n; ii ++) {
            int pos = 0;
            while(pos < m && A[pos] < B[ii]) {
                pos ++;
            }
            for(int jj = m; jj > pos; jj --) {
                A[jj] = A[jj - 1];
            }
            A[pos] = B[ii];
            m ++;
        }
    }
};