今天发现一个蛋疼的问题,服务端返回的urlString里面有时含有中文,使用
[NSURL URLWithString:urlString]生成URL对象时,iOS客户端不能正确进行网络请求,网上找到的URLEncode方法又不能完全解决问题.
方法1:
NSString* encodedString = [urlStringstringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
方法2:
NSString * encodedString = (NSString *)CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,(CFStringRef)urlString,NULL,NULL,kCFStringEncodingUTF8);
这两种方法当urlString里含有中文时URL编码是正确的,但是如果其中含有已转义的%等符号时,又会再次转义而导致错误.
查看方法2参数说明:
CFStringRefCFURLCreateStringByAddingPercentEscapes(CFAllocatorRefallocator, CFStringRef originalString, CFStringRefcharactersToLeaveUnescaped, CFStringReflegalURLCharactersToBeEscaped, CFStringEncoding encoding);
因此做出修改,写出方法:
NSString *encodedString = (NSString *)
CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,
(CFStringRef)urlString,
(CFStringRef)@"!$&'()*+,-./:;=?@_~%#[]",
NULL,
kCFStringEncodingUTF8);
如果在所有的类里都要用到这个方法,可以写成category,然后在头文件import "NSString+URL.h" 即可调用.
NSString+URL.h 文件
- @interface NSString (URL)
- - (NSString *)URLEncodedString;
- @end
- #import "NSString+URL.h"
- @implementation NSString (URL)
- - (NSString *)URLEncodedString
- {
- NSString *encodedString = (NSString *)
- CFURLCreateStringByAddingPercentEscapes(kCFAllocatorDefault,
- (CFStringRef)self,
- (CFStringRef)@"!$&'()*+,-./:;=?@_~%#[]",
- NULL,
- kCFStringEncodingUTF8);
- return encodedString;
- }
- @end
调用方法:
NSString *encodedString = [urlString URLEncodedString];
//encodedString do something
本文转载自:http://blog.youkuaiyun.com/typingios/article/details/9136005