php判断正常访问和外部访问

anjueci1221

于 2014-01-07 15:05:00 发布

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文章标签： php

原文链接：http://www.cnblogs.com/fuhaots2009/p/3508894.html

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php判断正常访问和外部访问

<?php
session_start();
if(isset($_POST['check'])&&!empty($_POST['name'])){
	if($_POST['check'] == $_SESSION['check']){
		echo "正常访问";
	}else{
		echo "外部访问";
	}
}
	$token = md5(uniqid(rand(),true));
	$_SESSION['check'] = $token;
?>
<form method="post" action="">
<input type="text" name="name"/>
<input type="text" name="check" value="<?=$token;?>">
<input type="submit">

转载于:https://www.cnblogs.com/fuhaots2009/p/3508894.html